a)\(\frac{2^{15}.3^2}{6^6.8^3.4}=\frac{2^{15}.3^2}{2^6.3^6.2^32^2}=\frac{2^{15}.3^2}{2^{\left(6+3+2\right)}.3^6}=\frac{2^{15}.3^2}{2^{11}.3^6}=\frac{2^{\left(15-11\right)}}{3^{\left(6-2\right)}}=\frac{2^3}{3^4}\) viết dài từng bước cho bạn dẽ hiểu

b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^{20-12}=2^8\)có thể đua về cơ số 4 thay cơ 2

\(\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{5}{8}-\frac{5}{10}+\frac{5}{11}+\frac{5}{12}}+\frac{\frac{3}{2}+1+\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}+\frac{5}{4}}\)

\(=\frac{3.\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}{5.\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{11}+\frac{1}{12}\right)}+\frac{3.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)}{5.\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)}\)

\(=\frac{3}{5}+\frac{3}{5}\)

\(=\frac{6}{5}\)

a) =-0,001 (số dau âm le bảo gì cũng (-) gia tri: =-\(\left(0,1=\frac{1}{10}\Rightarrow\left(\frac{1}{10}\right)^3=\frac{1}{10^3}=\frac{1}{1000}=0,001\right)\) 

b)\(\frac{8^{10}+4^{10}}{8^4+4^{^{11}}}=\frac{4^{20}+4^{10}}{4^8+4^{11}}=\frac{4^{10}\left(1+4^{\left(20-10\right)}\right)}{4^8\left(1+4^{\left(11-8\right)}\right)}=\frac{4^{10-8}.\left(1+4^{10}\right)}{1+4^3}=\frac{4^2\left(1+4^{10}\right)}{1+64}\)

1.hiệu rồi thi  tích

2.chưa hiểu hỏi tiếp

3.chưa tích quay về điều 1

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)

Chúc học tốt :)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)

\(M=\frac{2^{20}}{2^{12}}\)

\(M=2^8=256\)

\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)

Vậy 

\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)

P/s; Ko chắc đâu nhé

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.2^8\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^8\)